Below is my command line
$ps -eaf | grep consul_exporter | grep -v grep root 4020 1 6 Mar20 ? 4-08:51:18 ./consul_exporter --consul.server=10.1.2.133:8500 --kv.prefix=/ --web.listen-address=0.0.0.0:80
I want to get output of IP address(10.1.2.133) alone as output. How to write command line for that?
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Answer
If you don’t mind a solution which is not elegant, but does the job, just pipe the output of your grep command into
... | cut -f 2 -d = | cut -f 1 -d :
This splits the line first by the = and then :. If the pattern is not so regular and the IP address can appear anywhere in the line, pipe it into
... | grep -oE '([0-9]{1,3}[.]){3}[0-9]{1,3}'
The -o option just extract the matching pattern(s) from the input.