After executing this
ta=`zcat abc.log.2019071814.gz |grep "R_MT"|grep "A:1234"|grep "ID:413"|awk -F"|" '{print $20}'|sort|uniq -c|awk '{$1=$1};1'`
Here $20 indicates the “S:” entry in each row (I am taking the unique count of all s values),I am getting result as
93070 S:1 11666 S:8 230 S:9
so what I need is the sum of all occurrence of s values .i.e 93070+11666+230 so result be total=104966
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Answer
$ echo 93070 S:1 11666 S:8 230 S:9 | sed -E 's,S:[0-9]+,,g' | sed 's, ,+,g' | bc - 104966