I have 20 files like:
01a_AAA_qwe.sh01b_AAA_asd.sh01c_AAA_zxc.sh01d_AAA_rty.shFiles have a similar format in their names. They begin with 01, and they have 01*AAA*.sh format.
I wish to copy and rename files in the same directory, changing the number 01 to 02, 03, 04, and 05:
02a_AAA_qwe.sh02b_AAA_asd.sh02c_AAA_zxc.sh02d_AAA_rty.sh03a_AAA_qwe.sh03b_AAA_asd.sh03c_AAA_zxc.sh03d_AAA_rty.sh04a_AAA_qwe.sh04b_AAA_asd.sh04c_AAA_zxc.sh04d_AAA_rty.sh05a_AAA_qwe.sh05b_AAA_asd.sh05c_AAA_zxc.sh05d_AAA_rty.shI wish to copy 20 of 01*.sh files to 02*.sh, 03*.sh, and 04*.sh. This will make the total number of files to 100 in the folder.
I’m really not sure how can I achieve this. I was trying to use for loop in the bash script. But not even sure what should I need to select as a for loop index.
for i in {1..4}; do cp 0${i}*.sh 0${i+1}*.shdonedoes not work.
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Answer
There are going to be a lot of ways to slice-n-dice this one …
One idea using a for loop, printf + brace expansion, and xargs:
for f in 01*.shdo printf "%sn" {02..05} | xargs -r -I PFX cp ${f} PFX${f:2}doneThe same thing but saving the printf in a variable up front:
printf -v prefixes "%sn" {02..05}for f in 01*.shdo <<< "${prefixes}" xargs -r -I PFX cp ${f} PFX${f:2}doneAnother idea using a pair of for loops:
for f in 01*.shdo for i in {02..05} do cp "${f}" "${i}${f:2}" donedoneStarting with:
$ ls -1 0*.sh01a_AAA_qwe.sh01b_AAA_asd.sh01c_AAA_zxc.sh01d_AAA_rty.shAll of the proposed code snippets leave us with:
$ ls -1 0*.sh01a_AAA_qwe.sh01b_AAA_asd.sh01c_AAA_zxc.sh01d_AAA_rty.sh02a_AAA_qwe.sh02b_AAA_asd.sh02c_AAA_zxc.sh02d_AAA_rty.sh03a_AAA_qwe.sh03b_AAA_asd.sh03c_AAA_zxc.sh03d_AAA_rty.sh04a_AAA_qwe.sh04b_AAA_asd.sh04c_AAA_zxc.sh04d_AAA_rty.sh05a_AAA_qwe.sh05b_AAA_asd.sh05c_AAA_zxc.sh05d_AAA_rty.shNOTE: blank lines added for readability