There are multiple directories which contain a file with the same name:
JavaScript
x
direct_afaap/file.txt
direct_fgrdw/file.txt
direct_sardf/file.txt
Now I want to extract them to another directory, direct_new
and with a different file name such as:
JavaScript
[mylinux~ ]$ ls direct_new/
file_1.txt file_2.txt file_3.txt
How can I do this?
BTW, if I want to put part of the name in original directory into the file name such as:
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[mylinux~ ]$ ls direct_new/
file_afaap.txt file_fgrdw.txt file_sardf.txt
What can I do?
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Answer
This little BaSH script will do it both ways:
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#!/bin/sh
#
# counter
i=0
# put your new directory here
# can't be similar to dir_*, otherwise bash will
# expand it too
mkdir newdir
for file in `ls dir_*/*`; do
# gets only the name of the file, without directory
fname=`basename $file`
# gets just the file name, without extension
name=${fname%.*}
# gets just the extention
ext=${fname#*.}
# get the directory name
dir=`dirname $file`
# get the directory suffix
suffix=${dir#*_}
# rename the file using counter
fname_counter="${name}_$((i=$i+1)).$ext"
# rename the file using dir suffic
fname_suffix="${name}_$suffix.$ext"
# copy files using both methods, you pick yours
cp $file "newdir/$fname_counter"
cp $file "newdir/$fname_suffix"
done
And the output:
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$ ls -R
cp.sh*
dir_asdf/
dir_ljklj/
dir_qwvas/
newdir/
out
./dir_asdf:
file.txt
./dir_ljklj:
file.txt
./dir_qwvas:
file.txt
./newdir:
file_1.txt
file_2.txt
file_3.txt
file_asdf.txt
file_ljklj.txt
file_qwvas.txt