extract some part of a list of strings and set the…

I have a list of file names I have tried to extract the index between sil. and .asc and put them in a list while I do not to have the repetition of indexes in my list. The following is some part of the list of my files.

ellip5.0.apo.3.sil.16.asc
ellip5.0.apo.3.sil.7.asc
ellip5.0.apo.3.sil.8.asc
ellip5.0.apo.4.sil.3.asc
ellip5.0.apo.4.sil.14.asc
ellip5.0.apo.4.sil.5.asc
ellip5.0.apo.4.sil.6.asc
ellip5.0.apo.4.sil.7.asc
ellip5.0.apo.4.sil.8.asc
ellip5.0.apo.5.sil.3.asc
ellip5.0.apo.5.sil.14.asc
ellip5.0.apo.5.sil.5.asc
ellip5.0.apo.5.sil.6.asc
ellip5.0.apo.5.sil.7.asc
ellip5.0.apo.5.sil.8.asc
ellip5.0.apo.6.sil.3.asc
ellip5.0.apo.6.sil.4.asc
ellip5.0.apo.6.sil.5.asc
ellip5.0.apo.6.sil.16.asc
ellip5.0.apo.6.sil.7.asc
ellip5.0.apo.6.sil.8.asc
ellip5.0.apo.7.sil.13.asc
ellip5.0.apo.7.sil.4.asc
ellip5.0.apo.7.sil.5.asc

The following code is my attempt to make the list but it doesn’t work

args=()
containsElement () {
  local e
  for e in "${@:2}"; do [[ "$e" == "$1" ]] && return 0; done
  return 1
}
for MYVAR in  "ellip*.asc"
j=0
for i in $(ls ellip*.asc)
do
  INDEX=`echo $i | grep -oE 'sil.[^/]+.asc' | cut -c5- | rev | cut -c5- | rev`
  listcontains INDEX "${args[@]}" 
  if [ $? == 1 ];then
        args[j]=$INDEX
        j=$(($j + 1))
        echo $INDEX
   fi
done
echo ${args[@]}

Any suggestion will be appreciated.. My expected list would be :

16 7 8 3 14 5 6 16 4 13

and preferably a sorted list.

Answer

You can use this script in BASH 4:

# declare an associative array
declare -A arr

for f in ellip*.asc; do
    f="${f/#*sil.}"
    f="${f%.asc}"
    arr["$f"]=1
done

# print sorted index values
printf "%sn" "${!arr[@]}" | sort -n
3
4
5
6
7
8
13
14
16

In older BASH where associative array is not supported use:

declare -a arr

for f in ellip*.asc; do
    f="${f/#*sil.}"
    f="${f%.asc}"
    arr+=("$f")
done

sort -un <(printf "%sn" "${arr[@]}")

Output:

Advertisement

Answer