Extract text with any command in linux shell

How do I extract the text from the following text and store it to the variables:

05:21-09:32, 14:21-19:30

Here, I want to store 05 in one variable, 21 in another, 09 in another and so on. All the value must me stored in array or in separate varibles.

I have tried:

k="05:21-09:32, 14:21-19:30"

part1=($k | awk -F"-" '{print $1}' | awk -F":" '{print $1}')                                                                                                                      
part2=($k | awk -F"-" '{print $2}' | awk -F":" '{print $1}')
part3=($k | awk -F"," '{print $2}' | awk -F":" '{print $1}')
part4=($k | awk -F"-" '{print $3}' | awk -F":" '{print $1}')

I need a more clear solution or short solution.

Answer

Your code has a number of problems.

• You can’t pipe the value of k to standard output with just $k — you want something like printf '%sn' "$k" or perhaps the less portable echo "$k"
• Notice also the quoting in the expression above; without it, the shell will perform wildcard expansion and whitespace tokenization on the value
• Spawning two Awk processes for a simple string substitution is excessive
• Spawning a separate pipeline for each value you want to extract is inefficient; if at all possible, extract everything in one go.

Something like IFS=':-, '; set -- $k will assign the parts to $1, $2, $3, and $4 in one go.