Get a radius of a circle in bash shell

I need to write a script to find radius of a circle and then find the area while the circumference is given

#!/bin/bash
echo -n "Enter the circumference: "
read CIRC
 PI=3.14
let RAD=$(($CIRC/((2*$PI )) )) 
let  AREA=$PI * $RAD * $RAD
echo "The area of a circle is: "$AREA""

JavaScript
​x
 
#!/bin/bashecho -n "Enter the circumference: "read CIRC PI=3.14let RAD=$(($CIRC/((2*$PI )) )) let  AREA=$PI * $RAD * $RADecho "The area of a circle is: "$AREA""​

The formula is: RADIUS=CIRCUMFERENCE/(2 * PI) The problem is I cant make this formula work because bash doesn’t accept decimal division I read a lot of answers there but still can’t get what I want

I have something like

let RAD=$(($CIRC/((2*$PI )) ))

JavaScript
 
let RAD=$(($CIRC/((2*$PI )) )) ​

was trying a lot of different variants,used bc -l but still can’t do it right and there are always a mistakes

Answer

echo -n "Enter the circumference: "
read CIRC
PI=3.14
RAD=`bc -l <<< "$CIRC/(2*$PI)"`
echo $RAD
AREA=`bc  -l <<< "$PI*$RAD*$RAD"`
echo "The area of a circle is: "$AREA""

JavaScript
 
echo -n "Enter the circumference: "read CIRCPI=3.14RAD=`bc -l <<< "$CIRC/(2*$PI)"`echo $RADAREA=`bc  -l <<< "$PI*$RAD*$RAD"`echo "The area of a circle is: "$AREA""​

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Answer