I have an output like this:
a/foo bar / b/c/foo sth /xyz cc/bar ghj /axz/byz
What i want is just this line:
a/foo bar /
To be more clear, I want those line ending with a specific string. I want to grep
lines that have a /
character at their last column.
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Answer
You can use $
like this:
$ grep '/$' file a/foo bar /
As $
stands for end of line, /$
matches those lines whose last character is a /
.