My bash code is simply this. I am trying to learn docker but also a newbie with bash scripting. I type in something simple like google.com for the read command but it gives me curl: (3) URL using bad/illegal format or missing URL. Anyone know what I am doing wrong?
docker exec -it missingDependencies sh -c "echo 'Input Website:'; read website; echo 'Searching..'; sleep 1; curl http://$website;"
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Answer
Curl will give that warning when invoked like this (without a domain):
curl http://let’s define an image that has curl.
$ cat Dockerfile FROM ubuntu:latest RUN apt-get update RUN apt-get install -y curland assemble it:
docker build . -t foobarSo now we can run your script.
$ docker run -it --rm foobar /bin/sh -c "set -x; echo 'Input Website:'; read website; echo 'Searching..'; curl https://$website ;"+ echo Input Website:Input Website:+ read websitegoogle.com+ echo Searching..Searching..+ curl https://Solution
docker run -it --rm foobar /bin/sh -c "set -x; read -p 'which website?: ' website; echo 'Searching..'; curl https://$website;"+ read -p which website?: websitewhich website?: google.com+ echo Searching..Searching..+ curl https://google.com<HTML><HEAD><meta http-equiv="content-type" content="text/html;charset=utf-8"><TITLE>301 Moved</TITLE></HEAD><BODY><H1>301 Moved</H1>The document has moved<A HREF="https://www.google.com/">here</A>.</BODY></HTML>The problem is that when you run bash -c “echo whatever $website”, the $website variable will be taken from your current environment and not from the docker environment (from read website). To counteract that the $website variable is interpolated, you could use single quotes like sh -c ‘read foo; echo $foo’, or escape the dollar sign: sh -c “read foo; echo $foo”