how to find lines that contain consecutive vowels
$ (filename) | sed '/[a*e*i*o*u]/!d'
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Answer
To find lines that contain consecutive vowels you should consider using
sed -n '/[aeiou]{2,}/p' file
Here, [aeiou]{2,}
pattern matches 2 or more occurrences ({2,}
is an interval quantifier with the minimum occurrence number set to 2
) and [aeiou]
is a bracket expression matching any char defined in it.
The -n
suppresses output, and the p
command prints specific lines only (that is, -n
with p
only outputs the lines that match your pattern).
Or, you may get the same functionality with grep
:
grep '[aeiou]{2,}' file grep -E '[aeiou]{2,}' file
Here is an online demo:
s="My boomerang Text here Koala there" sed -n '/[aeiou]{2,}/p' <<< "$s"
Output:
My boomerang Koala there