How to make a return from a child function cause a return to the parent function?

I have a parent function and child function:

parent() {

   child aa1 bb1 cc1
   child aa2 bb2 cc2
   child aa3 bb3 cc3
   child aa4 bb4 cc4

}

child() {
  ....
  if [ some error reason ]; then return 1; fi
  ...
}

How to make the return 1 (of the child) cause a return in the parent and then avoid the execute the remaining child calls?

without adding a check of the returned value after each child call like this

parent() {

   child aa1 bb1 cc1
   e=$?; [ "$e" != "0" ] && return $e
   child aa2 bb2 cc2
   e=$?; [ "$e" != "0" ] && return $e
   child aa3 bb3 cc3
   e=$?; [ "$e" != "0" ] && return $e
   child aa4 bb4 cc4
   e=$?; [ "$e" != "0" ] && return $e

}

Answer

There is a solution other than set -e and || return

It’s simple, just use exit instead of return and the parent should called in a sub-shell:

parent() {
   child aa1 bb1 cc1
   child aa2 bb2 cc2
   child aa3 bb3 cc3
   child aa4 bb4 cc4
}

child() {
  ....
  if [ some error reason ]; then exit 1; fi
  ...
}

And I call the parent in this way:

( parent )