How can I repeat the character - n times in shell? I have read and tried this, but this does not work for -. It throws error invalid option. Below is the exact command that I used:
printf '-%.0s' {1..100}
Original posted line: printf '-%0.s' {1..100}
I also tried escaping - by putting a but in that case it repeats - n times.
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Answer
This throws an error:
$ printf '-%.0s' {1..100}; echo ""
bash: printf: -%: invalid option
printf: usage: printf [-v var] format [arguments]
This works fine under bash:
$ printf -- '-%.0s' {1..100}; echo ""
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For other shells, try:
printf -- '-%.0s' $(seq 100); echo ""
The problem was the printf expects that - starts an option. As is common among Unix/POSIX utilities in this type of situation, -- signals to printf to expect no more options.