Issue finding the process id from shell scipt

mySample.sh

pid=$(ps -Af | grep $1 | grep -v grep | awk ' { print $2 } ');  
echo $pid

The above command is printing and killing the temporary process that was created for grep Even though i do not have any process running with Abcd, This is printing pid Any ways to ignore it, iam actually ignoring it using grep -v, still…

./mySample.sh Abcd
 6251 6378 6379

Any Issue in fetching the process id.?

Basic command line output is below,After running a process with name Acc_Application_One

[root@localhost Desktop]# ps -Af | grep Acc

root 6251 2758 0 16:16 pts/1 00:00:00 ./Acc_Application_One

root 7288 2758 0 16:57 pts/1 00:00:00 grep Acc

Changed mySample.sh

    pgrep -fl "$1" 

And the output is

[root@localhost Desktop]# mySample.sh Acc_Application_One

6251 7289

Answer

To kill a process with the pattern anywhere in command line use pkill -f:

pkill -f "$1"

As per man pkill:

-f Match the pattern anywhere in the full argument string of the process instead of just the executable name.

Similarly you can use pgrep -f "$1" to list the process id of the matching process.