When i input a variable on the curl with the json indexed, it takes the string value of the variable, if i scaped the double-quotes, it returns me a sintax error because of in a json request u have to input the data with double-quotes. Example:
#!/bin/bash
token="x"
tokenPass="x"
name="prueba"
url="https://prueba.prueba.prueba"
user="prueba"
pass="prueba"
notes="prueba"
curl -k -H "Content-Type:Application/json" -d '{"jsonrpc": "2.0", "method": "account/create", "params": { "authToken": "$token", "tokenPass": "$tokenPass", "name": "$name" , "categoryId": "7", "clientId": "9","login":"$user","url": "$url" ,"pass": "$pass","notes": "$notes"}, "id": 1}' -o- https://syspass.prueba.es/api.php
The curl json request works if i input the data manually, but with the variables, when i create the account, the account is named as the string value of the variable, i mean, if the variable is named $name , the account created is name $name. Any help please? Also i tried to input the variable: “${variable}” and either works
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Answer
Try this:
curl -k -H "Content-Type:Application/json" -d '{"jsonrpc": "2.0", "method": "account/create", "params": { "authToken": "'${token}'", "tokenPass": "'${tokenPass}'", "name": "'${name}'" , "categoryId": "7", "clientId": "9","login":"'${user}'","url": "'${url}'" ,"pass": "'${pass}'","notes": "'${notes}'"}, "id": 1}' -o- https://syspass.prueba.es/api.php
A bit of explanation:
Text that is between single quotes ' will not be interpreted by bash and that is why the variables will not be inserted. You have to break the string up…
An other suggestion is that you should use curly braces around variables: When do we need curly braces around shell variables?