Obtaining file names from directory in Bash

I am trying to create a zsh script to test my project. The teacher supplied us with some input files and expected output files. I need to diff the output files from myExecutable with the expected output files.

Question: Does $iF contain a string in the following code or some kind of bash reference to the file?

#!/bin/bash
inputFiles=~/project/tests/input/*
outputFiles=~/project/tests/output

for iF in $inputFiles
do
./myExecutable $iF > $outputFiles/$iF.out
done

Note:

Any tips in fulfilling my objectives would be nice. I am new to shell scripting and I am using the following websites to quickly write the script (since I have to focus on the project development and not wasting time on extra stuff):

Grammar for bash language

Begginer guide for bash

Answer

As your code is, $iF contains full path of file as a string.

N.B: Don’t use for iF in $inputFiles

use for iF in ~/project/tests/input/* instead. Otherwise your code will fail if path contains spaces or newlines.