I'm very new to linux and bash. I'm trying to find a domain name for an ip address. When I use nslookup I have a bunch of lines like this Output I only want to print www.computerhope.com in the second line. How do I do this? Also I tried to use host command as well. It looks cleaner. How do

Print a certain line in linux or options for nslookup

I’m very new to linux and bash. I’m trying to find a domain name for an ip address. When I use nslookup I have a bunch of lines like this

nslookup 204.228.150.3

Output

Server: 198.60.22.2
Address: 198.60.22.2#53

Non-authoritative answer:
3.150.228.204.in-addr.arpa name = www.computerhope.com.

Authoritative answers can be found from:
150.228.204.in-addr.arpa nameserver = ns.xmission.com.
150.228.204.in-addr.arpa nameserver = ns1.xmission.com.
150.228.204.in-addr.arpa nameserver = ns2.xmission.com.
ns.xmission.com Internet address = 166.70.254.2
ns1.xmission.com Internet address = 204.228.159.2
ns2.xmission.com Internet address = 207.135.133.2

I only want to print www.computerhope.com in the second line. How do I do this? Also I tried to use host command as well. It looks cleaner.

206.153.126.75.in-addr.arpa domain name pointer www.cyberciti.biz.

How do I only print www.cyberciti.biz when I use host command ? PLease help

Answer

$ host 75.126.153.202 |sed -e 's/.* //'
www.cyberciti.biz.

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Answer