print the count of files for each sub folder iterativly

I have the following folder structure:

A/B/C/D/E/00
A/B/C/D/E/01
.
.
A/B/C/D/E/23

Similarly,

M/N/O/P/Q/00
M/N/O/P/Q/01
.
.
M/N/O/P/Q/23

Now, each folder from 00 to 23 has many files inside, which I would like to count.

If I run this simple command:

ls /A/B/C/D/E/00 | wc -l I can get the count of files in each of these sub directories. I want to automate this or get it iteratively. Also, the final output I am looking at is a file that should look like this:

C E RESULT OF ls /A/B/C/D/E/00 | wc -l RESULT OF ls /A/B/C/D/E/01 | wc -l
M Q RESULT OF ls /M/N/O/P/Q/00 | wc -l RESULT OF ls /M/N/O/P/Q/01 | wc -l

So, the output should look like this finally

C E 23 23 4 6  7  4 76 98 57 2 67 9 12 34 67 0 2 3  78 98 12 3  57 213
M Q 12 10 2 34 32 1 35 65 87 8 32 2 65 87 98 0 4 12 1  35 34 76 9  67

Please note, the values after the alphabets are the values of file counts of the 24 folders 00, 01 through 23.

Using the eval approach: I can hardcode and get the exact results. But, I wanted it in a way that would show me the data for the previous day. So this is what I did:

d=`date --date ="1 days ago" +%Y%m%d`
month= `date +%Y%m`
eval echo YZ $d '"$(ls "/A/B/YZ/$month/$d/"'{20150800..20150823})'| wc -l)"'

This works perfectly because in the given location there are files inside child directories 20150800,20150801..20150823. However when I try to generalize this like below, it shows no such file or directory:

eval echo YZ $d '"$(ls "/A/B/YZ/$month/$d/"'{"$d"00.."$d"23})'| wc -l)"'

Is there something I am missing in the above line?

Answer

A very safe way of counting files:

find . -mindepth 1 -exec printf x ; | wc -c

To not count recursively add -maxdepth 1 before -exec.

Some other notes:

eval is evil. Don’t use it. There is only one place I’ve ever seen where it’s appropriate, and that’s when using getopt.
You should not parse the output of ls.
Use $() for command substitutions.

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Answer