print the count of files for each sub folder iterativly

I have the following folder structure:

A/B/C/D/E/00
A/B/C/D/E/01
.
.
A/B/C/D/E/23

Similarly,

M/N/O/P/Q/00
M/N/O/P/Q/01
.
.
M/N/O/P/Q/23

Now, each folder from 00 to 23 has many files inside, which I would like to count.

If I run this simple command:

ls /A/B/C/D/E/00 | wc -l I can get the count of files in each of these sub directories. I want to automate this or get it iteratively. Also, the final output I am looking at is a file that should look like this:

C E RESULT OF ls /A/B/C/D/E/00 | wc -l RESULT OF ls /A/B/C/D/E/01 | wc -l
M Q RESULT OF ls /M/N/O/P/Q/00 | wc -l RESULT OF ls /M/N/O/P/Q/01 | wc -l

So, the output should look like this finally

C E 23 23 4 6  7  4 76 98 57 2 67 9 12 34 67 0 2 3  78 98 12 3  57 213
M Q 12 10 2 34 32 1 35 65 87 8 32 2 65 87 98 0 4 12 1  35 34 76 9  67

Please note, the values after the alphabets are the values of file counts of the 24 folders 00, 01 through 23.

Using the eval approach: I can hardcode and get the exact results. But, I wanted it in a way that would show me the data for the previous day. So this is what I did:

d=`date --date ="1 days ago" +%Y%m%d`
month= `date +%Y%m`
eval echo YZ $d '"$(ls "/A/B/YZ/$month/$d/"'{20150800..20150823})'| wc -l)"'

This works perfectly because in the given location there are files inside child directories 20150800,20150801..20150823. However when I try to generalize this like below, it shows no such file or directory:

eval echo YZ $d '"$(ls "/A/B/YZ/$month/$d/"'{"$d"00.."$d"23})'| wc -l)"'

Is there something I am missing in the above line?

Answer

A very safe way of counting files:

find . -mindepth 1 -exec printf x ; | wc -c

To not count recursively add -maxdepth 1 before -exec.

Some other notes:

• eval is evil. Don’t use it. There is only one place I’ve ever seen where it’s appropriate, and that’s when using getopt.
• You should not parse the output of ls.
• Use $() for command substitutions.