Print value of by loop in the end of line in bash

My file which run loop…

$cat /wdc-cron/countries.csv
c-ac,ascension_island
c-ad,andorra
c-ae,united_arab_emirates

My program file

yesterday=$(date --date "1 days ago" +%F)

while IFS= read -r line
do

dir=$(echo $line | awk -F, '{print $1 }')
country=$(echo $line | awk -F, '{print $2 }')

cd /$dir.whoisdatacenter.com

echo $country >> /wdc-cron/count-$yesterday.txt
cat /$dir.whoisdatacenter.com/$yesterday-$country-email.csv | wc -l >> /wdc-cron/count-$yesterday.txt

 awk '{print $country,",",$dir}' 

done < "/wdc-cron/countries.csv"

My result is

cat count-2020-01-22.txt 
ascension_island
0
andorra
0
united_arab_emirates
32

My should I do so result come like

ascension_island, 0
andorra, 0
united_arab_emirates, 32

I will be very glad if someone can help me out,

Answer

A possible solution would be to replace the line:

echo $country >> /wdc-cron/count-$yesterday.txt

with:

printf "$country, " >> /wdc-cron/count-$yesterday.txt

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Answer