We can print the current time with the builtin printf
function, without needing to invoke an external command like date
, like this:
printf '%(%Y-%m-%d:%H:%M:%S)T %sn' -1 # sample output: 2019-03-30:17:39:36,846
How can we make printf to print milliseconds or nanoseconds as well? Using %3N
or %N
in the format string doesn’t work:
printf '%(%Y-%m-%d:%H:%M:%S,%3N)T %sn' -1 # outputs 2019-03-30:17:38:16,%3N printf '%(%Y-%m-%d:%H:%M:%S,%N)T %sn' -1 # outputs 2019-03-30:17:38:16,%N
However, the date command works fine:
date +%Y-%m-%d:%H:%M:%S,%3N # gives 2019-03-30:17:39:36,846 date +%Y-%m-%d:%H:%M:%S,%N # gives 2019-03-30:17:39:36,160643077
This is on a Red Hat Linux version 7.3.
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Answer
In bash
5, you can get microsecond precision from EPOCHREALTIME
. However, printf
itself has no way to access that directly, so you need to extract the microseconds yourself.
$ echo $EPOCHREALTIME; printf '%(%F:%T)T.%dn' "$EPOCHSECONDS" "${EPOCHREALTIME#*.}"; echo $EPOCHREALTIME 1554006709.936990 2019-03-31:00:31:49.937048 1554006709.937083
This takes a little time, but the result appears to be accurate to about 0.05 milliseconds.