Below is the sample log:
2020-10-14 00:05:44,621 debug [org.jboss.as] ............... 2020-10-14 00:05:45,560 debug [org.jboss.as] ............... 2020-10-14 00:05:46,222 debug [org.jboss.as] ............... 2020-10-14 00:05:46,608 debug [org.jboss.as] ...JBoss .... server is started ............
Below is the desired output:
2020-10-14 00:05:46,608 debug [org.jboss.as] ...JBoss .... server is started ............
When I use awk if it is exact time it will display the output otherwise it not displaying the output. Below is the code:
Not displaying output:
awk /'2020-10-14 00:05:46,607'/ '/home/notyo/application.log' | grep -e 'JBoss.*started'
Displaying output:
awk /'2020-10-14 00:05:46,608'/ '/home/notyo/application.log' | grep -e 'JBoss.*started' 2020-10-14 00:05:46,608 debug [org.jboss.as] ...JBoss .... server is started ............
Besides that I got to find a solution. Below works but not as expected.
Displaying output as expected:
grep -e 'JBoss.*started' '/home/notyo/application.log' | awk '$0 >= "2020-10-14 00:05:46,608"' 2020-10-14 00:05:46,608 debug [org.jboss.as] ...JBoss .... server is started ............
Displaying output. Expecting that it should not display as using >
grep -e 'JBoss.*started' '/home/notyo/application.log' | awk '$0 > "2020-10-14 00:05:46,608"' 2020-10-14 00:05:46,608 debug [org.jboss.as] ...JBoss .... server is started ............
Can I know why such behaviour. Could you advice what is the correct approach?
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Answer
If you compare the strings with $0 > "2020-10-14 00:05:46,608", it will compare the string 2020-10-14 00:05:46,608 debug [org.jboss.as] ...JBoss .... server is started ............ with a string 2020-10-14 00:05:46,608 which returns true.
In order to compare only date and time portion, please try instead:
grep -e 'JBoss.*started' '/home/notyo/application.log' | awk '($1" "$2) > "2020-10-14 00:05:46,608"'
If you want to include the exact time above, please replace > with >=, which also works as you expect.