Status after each argument passed to -exec in find

I’m writing a quick script to list all the files in a directory, run a function on each of them, and then print out the status code. Now the status code I would like is of the entire transaction and not the last expression that was executed. For example…

find ./ -maxdepth 1 -name *.txt -exec my_function {} ;

Let’s say I have the following files file1.txt, file2.txt, file3.txt in my directory. When file1.txt gets passed to -exec its status code is 1 but calls to file2.txt and file3.txt return 0. When I call echo $? at the end it returns 0 from the last expression executed despite the call on file1.txt returning a 1. What I would like is a status code that’s nonzero if any of the expressions return a nonzero value in the above script just like what was described for file1.txt. How would I go about that?

Answer

I will suggest something like this:

status=0
while IFS= read -d '' -r file; do
   my_function "$file"
   ((status |= $?))
done < <(find . -maxdepth 1 -name '*.txt' -print0)

echo "status=$status"

This will print status=1 if any of the exist status is 1 from my_function.