I have two files, file1 and file2. I want to compare several columns – $1,$2 ,$3 and $4 of file1 with several columns $1,$2, $3 and $4 of file2 and print those rows of file2 that do not match any row in file1. E.g. file1 file2 I want to have as output: I have seen questions asked here for finding
Tag: awk
How To replace leading zero with spaces in linux?
i have text like this i want to the result like this i have been searching all over and get no result, please help Answer With gawk you can use gensub: Or same pattern with sed:
Fastest way to extract pattern
What is the fastest way to extract a substring of interest from input such as the following? Desired output (i.e., the :-terminated string following the string MsgTrace(65/26) in this example): noop I tried the following, but without success: Answer grep by default returns the entire line when a match is found on a given input line. While option -o restricts
Re-arranging lines after a pattern in a file according to a specific order
I have a large log file with the below format I have created a shell script that insert those values in the database in the same order val1, val2, val3 ,val4 The problem is that the files sometimes gets corrupted and the variables come in different order, like below for example: Using shell script, I want to rearrange the lines
AWK – Show lines where column contains a specific string
I have a document (.txt) composed like that. And I want to show some information by column. For example, I have some different information in “info3” shield, I want to see only the lines who are composed by “test” in “info3” column. I think I have to use sort but I’m not sure. Any idea ? Answer You can use
How to grep string and show previous word in a Linux file
i have a file with a lot of IPs and each IP have an ID, like this: Below this Ips and after these Ips the file have more information, its a output to an API call.. I need, grep a IP and then the command shows the id, just the number. Like this: EDIT: More information, the ip will be
How to remove certain lines of a large file (>5G) using linux commands
I have files which are very large (> 5G), and I want to remove some lines by the line numbers without moving (copy and paste) files. I know this command works for a small size file. (my sed command do not recognize -i option) This command takes relatively long time because of the size. I just need to remove the
How To Delete A File Every X Times A Script Is Run – Manage A Log File From Inside A Script?
I would normally just schedule this as a cron job or script, however, I would like to delete a log file (it’s constantly appended to every time a script runs) only after 50 times. Needed Inside The Script: The thing is, since the script does not run consistently, it has be to be implemented within the script itself. Please note:
Converting date format in bash
I have similar different file of the format backup_2016-26-10_16-30-00 is it possible to rename using bash script to backup_26-10-2016_16:30:00 for all files. Kindly suggest some method to fix this. Original file: backup_2016-30-10_12-00-00 Expected output: backup_30-10-2016_12:00:00 Answer To perform only the name transformation, you can use awk: As fedorqui points out in a comment, awk’s printf function may be tidier in
Storing awk manipulation in variable
I have two text files in tab delimted format like following. file_1 file_2 these two file contents were stored into two different variables. Now I would like extract the lines which has “+” symbol in column 4 and store it in the variable and later print it. But it throws me error message: Here is my code which I tried