The following is the output of the command ads2 cls create However, I’m trying to extract the value of name and state for each node, save them in a variable and display them in the following order: Till now i, with the help of this so much powerful learning site, could extract the values of name and sta…
Tag: cut
Trying to find empty files in other user home directory
I want to search for empty files inside the home directory of the user “adam” for example. Now i don’t know the right path for that user, so I need to get it from /etc/passwd with the following command: Output: /home/adam (for example) Then executing this command to find the empty files. Is …
Extract all unique URL from log with only POST type of the request
I’ve got a log file with the such type of the records: 41.201.181.27 – [2019-04-06 18:22:02] “GET /images/stands/photo_mois.jpg HTTP/1.1” 304 – “http://example.com/popup.php?choix=mois” “Mozilla/4.0” “-” I’ve got the script for getting al…
Linux split a file in two columns
I have the following file that contains 2 columns : How is possible to split the file in 2 other files, each column in a file like this: File1 File2 Answer Perl 1-liner using (abusing) the fact that print goes to STDOUT, i.e. file descriptor 1, and warn goes to STDERR, i.e. file descriptor 2: You could, of co…
Linux cut, paste
I have to write a script file to cut the following column and paste it the end of the same row in a new .arff file. I guess the file type doesn’t matter. Current file: The output should be: how can I do this? using a Linux script file? Answer Brief explanation, ^([^,]*) would match the first field which…
Ubuntu bash script grepping and cutting on first column
I am trying to implement a bash script that will take the piped input and cut the first column and return a total. The difference is that the cut is not from a file, but from the piped input. For example: Basically, in my scenario the first column will always be from the passed input. Example usuage is: data.…
Convert number from text file
I have a file: id name date 1 paul 23.07 2 john 43.54 3 marie 23.4 4 alan 32.54 5 patrick 32.1 I want to print names that start with “p” and have an odd numbered id My command: grep “^p” filename | cut -d ‘ ‘ -f 2 | …. result: paul patrick Answer Awk can do it all:
Using cut to remove until a delimiter from end
I have a string with many delimiters like : abcd – efgh – foobar.extension (Delimiter ‘-‘) I want to remove the So far, I have done But this does not help as it echo’s I want to be able to keep the inital part before the final delimiter(‘-‘) is found. Answer In bash y…
Linux cut pattern from log file
i have json log file but theres not only json i need to cut/remove everything what isnt json, structure looks like this: i tried cut -d command but it doesnt work for me Answer This did the work:
Empty string as a output field seperator for Cut
How can I use cut with –output-delimiter=””? I want to join two columns using cut. I tried the following command. However cat -v shows that there are non printable characters. Specifically “^@”. Any suggestions to how can I overcome this? This is the content of my file 011,IBM,Pa…