Tag: grep

How can I show only some words in a line using sed?

I’m trying to use sed to show only the 1st, 2nd, and 8th word in a line. The problem I have is that the words are random, and the amount of spaces between the words are also random… For example: Is there a way to get this to output as just the 1st, 2nd, and 8th words: Thanks for any

How to find all files on a *NIX server containing a certain string

centos grep linux

I want to produce a list of every file on my server that contains a certain email address within the file. Starting with htdocs and all of its sub-directories. I am using this command: I seem to be getting the files that contain the string, but I am alos getting a listing of all directories, which I do not want

How to “grep” in array with dot “.” precisely?

arrays grep linux shell

I’m trying to check if the user input $1 exist in an array. And here is my code: What I expect is only “aaa.bbb.ccc” or “ccc.ddd.aaa” can be found. However, in this case, like “aaa” or “ccc” can also pass the validation. Seems like the dot is not treated as part of the string. Should I use regex or other

Search and Replace under linux?

grep linux sed

I tried the following but not adding ” this example I want to replace FILENAME_LOGIN to ‘login.php’ Tried this: However, it gives me login.php not ‘login.php’ Thanks Answer You only need sed for this:

Read the log files and get the entries between two dates

bash grep linux

I want to extract some information from the access log file that matches a keyword and between two dates. For ex. I want to find log entries between two dates that contains text “passwd”. For now, I am using the following command but not getting the correct results: Date format is [22/Feb/2017:17:28:42 +0000]. I have searched and look at this

Why doesn’t grep -lv work?

grep linux

I want to print out the name of a file if and only if it does not contain the string foo. However, if file contains foo and I run this file is outputted. Why does this happen and what can I do to work around it? Answer -v means to match any line that doesn’t match the pattern. So -lv

grep issues when using two files – I’ve tried everything

awk fastq grep linux unix

I have two files (recode and reads) that were built and saved with nano command and I want to compare what has on recode to reads and extract the lines in reads that overlaps. I have been trying to create a when loop with the previous logic on mind, but without success so far. The output data is not matching

Grep Pattern matching- underline

grep linux regex

I’ve not been able to find anything online to help so hoping someone may have an idea. What does an underline in an expression mean when using grep? For example: [_a-zA-Z0-9] Could someone help to explain the purpose here? Answer The grep command uses a regular expression as it is also described in the manpage of grep: A regular expression

How to grep two IP addresses and increase the value of the last number?

bash grep linux

I’m pretty new to Linux and writing scripts etc. I have this task where I need to find an IP-address from a database and then grep a bunch of files with this IP and the next one to see, if they have any presence there. Currently I have to first write: and then And I have to manually change the

Running statistics on multiple lines in bash

awk bash grep linux sed

I have multiple HTTP headers in one giant file, separated with one empty line. I have approximately 10,000,000 of headers separated with an empty line. If I want to discover trends, like header order, I want to do aggregate headers to a one-liner (how I can aggregate lines ending with an empty line and do that separately for all headers?):