Tag: shell

Linux is there a way to list a specified number of lines in a repository and sub repositories

I want to write a shell script which takes as input a valid path, and the script lists the first n (also a parameter) lines of all the files from the repository and sub repositories where the user who launched the script has read and write privileges. Is there a command that would allow me to do this? I believe

How can I loop for end of month date between to dates in sh?

bash linux shell unix

I want to loop and print end of month date between two dates. I have below code but it prints day on day. but I want these result for: 20210131 20210228 20210331 thanks in advance Answer Something like this or with -m flag

Bash script return to menu if status code inside of a while loop [closed]

bash linux shell

Closed. This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 2 years ago. Improve this question I’m doing a bash script to check cryptocurrency prices, and it updates in a while loop like this: Crypto prices real time updating While loop

How can I build a Trap function with any key

bash linux shell

This function exits my script when I press cntr+C, how can i modify it to make it works when I press enter? Answer This might help:

Redirect file in linux using length [closed]

linux shell substring unix

Closed. This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 2 years ago. Improve this question Am trying to redirect the file based on the length. I have a file having the value, I like Linux I have to create a

how to run complex awk command on remote machine

awk bash linux shell ssh

I am trying to capture the total used memory in % on remote machine as the following so we add backslash as before the “$” as but still with the same errors any advice how to fix this syntax? Answer You also have to escape the double quotes “:

pass the date from outside as a parameter

awk linux sh shell unix

This is my Linux script, I want to ask the user from outside what date is needed, then save that date and run the script for that date. now currently this script generate a csv for the current date files, I want to run this for a user request date, can I pass parameters from outside? any help could be

awk renamed few files and left few to renamed

awk file-rename linux mv shell

I am trying to replace part of filenames based on matching string of filename from another file. Filenames are in following format: where digits before first _ represent station code, which I want to replace with its station name from another file named radiosonde.csv. For example : I want change 36872_20190806_00.csv to ALMATY_20190806_00.csv change 38064_20190806_00.csvto KYZYLORDA_20190806_00.csv Data of radiosonde is

Sed to replace a speccificc part of line by argument in shell script based in line number

bash linux sed shell

I have a script test.sh He has some arguments like : I made a while read loop to replace each specific part of a line (extractReplaceArgLine) with argument passed in shell script (Forest Cuba World Hello). Consider the file test.txt : So, the output would be : How can I do that ? Thanks ! Answer Use $1 to get

Any idea how i can use timeout command with condition in linux and shell script

linux shell

aim working on some shell script , i would like to check the following command df -h if timeout more than 60 second then echo “error ” else pass. so if this command will not responding for 1 minute then I will receive and error message , otherwise it will pass , any creative idea will be high apricated .