I am writing a small python script to for automatic student homework evaluation. I have a skeleton, where submitted homework is unzipped into a temporary folder and my script is called with path to the temporary folder as an argument.
My script first copies over some extra files I need and then tries to compile c++ code roughly like this:
compilation_files = " ".join(glob.iglob("*.cpp"))
compilation_call = ["g++", "-std=c++14", compilation_files, "-o " + output_name]
subprocess.call(compilation_call)
g++ exits with this error:
g++: error: tests-main.cpp tests-small1.cpp small1.cpp: No such file or directory g++: fatal error: no input files
I am sure the files exist (after all, glob wouldn’t be able to find them otherwise), and that the subprocess is executed in the correct directory.
I did this
print "ls: ", subprocess.check_output("ls")
print "pwd: ", subprocess.check_output("pwd")
print "files: ", compilation_files
to verify that the files are indeed there, are called properly and the script is being run in the correct directory.
— edit —
I can make the script work by passing shell=True, but that would also mean manually escaping file names for shell.
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Answer
Hmm, you are calling a subprocess with a list of arguments. First is the name of the command that will be executed, following ones are the arguments of the command one at a time.
So you are executing something like:
g++ -std=c++14 "tests-main.cpp tests-small1.cpp small1.cpp" -o xxx
and the error says that the file (singular file not plural files) "tests-main.cpp tests-small1.cpp small1.cpp" does not exist.
You should instead do:
compilation_call = ["g++", "-std=c++14"] + glob.iglob("*.cpp") + [ "-o " + output_name]
to have each individual file name in its own parameter list item.