I have a directory containing a large number of directories. Each directory contains some files and in some cases another directory.
JavaScript
x
parent_directory
sub_dir_1
sub_dir_1.txt
sub_dir_1_1.txt
sub_dir_2
sub_dir_2.txt
sub_dir_2_1.txt
sub_dir_3
sub_dir_3.txt
sub_dir_3_1.txt
sub_dir_4
sub_dir_4.txt
sub_dir_4_1.txt
sub_dir_5
sub_dir_5.txt
sub_dir_5_1.txt
I need to check that each sub_dir contains at least one file with the exact same name. I don’ need to check any further down if there are sub directories within the sub_dirs.
I was thinking of using for d in ./*/ ; do (command here); done
but I dont know how to get access to the sub_dir name inside the for loop
JavaScript
for d in ./*/ ;
do
(if directory does not contain 1 file that is the same name as the directory then echo directory name );
done
What is the best way to do this or is there a simpler way?
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Answer
from the parent directory
JavaScript
find -maxdepth 1 -type d -printf "%fn" |
xargs -I {} find {} -maxdepth 1 -type f -name {}.txt
will give you the name/name.txt pair. Compare with the all dir names to find the missing ones.
UPDATE
this might be simpler, instead of scanning you can check whether file exists or not
JavaScript
for f in $(find -maxdepth 1 -type d -printf "%fn");
do if [ ! -e "$f/$f.txt" ];
then echo "$f not found";
fi; done