I am writing a bash script to automatically detect when my USB keyboard is plugged into my laptop (running Ubuntu 14), so I can change the keyboard layout automatically.
Here is my code so far (I got it from another post on Stack Overflow so I’m not 100% sure how it works)
JavaScript
x
#!/bin/bash
setxkbmap es
for dev in /sys/bus/usb/devices/ *-*:*
do
if [ -f $dev/bInterfaceClass ]
then
if [[ "$(cat $dev/bInterfaceClass)" == "03" && "$(cat $dev/bInterfaceProtocol)" == "01" ]]
then
setxkbmap gb
fi
fi
done
I have got this to run on startup so far… But I’d like it to run every time a USB device is connected or disconnected.
It is important that I have it all run in one Bash script and not as a .rules file in …udev/… or anything. However, a single Python script will do just as well.
Advertisement
Answer
Thanks to ralf htp I was able to come up with the following solution. It has the following improvements:
- It is not dependent on specific keyboards, it will treat all USB keyboards in the same way.
- If the user manually switches to a different keyboard layout (one which is neither the default or the USB keyboard’s) it will not automatically switch it back to the default or USB layout.
Please feel free to improve this code at GitHub Gist
JavaScript
#!/bin/bash
kbd1=es #default keyboard layout
kbd2=gb #USB keyboard layout
flag=0
while true
do
layout="$(setxkbmap -query | grep -a layout | cut -c13-14)"
if [[ $layout == $kbd1 ]] || [[ $layout == $kbd2 ]]
then
for dev in /sys/bus/usb/devices*-*
do
if [ -f $dev/bInterfaceClass ]
then
if [[ "$(cat $dev/bInterfaceClass)" == "03" && "$(cat
$dev/bInterfaceProtocol)" == "01" ]]
then
if [[ "$flag" == "0" ]]
then
setxkbmap $kbd2
fi
flag=1
break
fi
if [[ "$flag" == "1" ]]
then
setxkbmap $kbd1
fi
flag=0
fi
done
fi
sleep 5s
done