Hoping someone can help me out here. Trying to run any command using exec() returns 126 and displays the same error message. I’ve narrowed it down to this pretty minimal test case. SELinux and PHP safe mode are not enabled permissions are fine on /, /bin/, and /bin/ls asterisk is a system user created with this command: adduser -d /var/lib/asterisk
Tag: exec
Exec command in Ant only executes first command
I want to list the permission of every script in directory dir/bin. But the below command only runs “ls” in the directory where the script is with below code rather than every script in dir/bin. Since script.xml is there in maindir, it just does a ls inside maindir. There are 2 problems: Performing ls -l & not just the 1st
php using exec with screen
I have a need to start three processes through my PHP script. Those processes live in the /home/user/server directory, named server-one, server-two and server-three. The process are also capable of accepting commands through their consoles, so I would need them to live in their own screen with a name so I can use -X stuff to give them commands. As
I do not understand how execlp() works in Linux
I have spent the last 2 days trying to understand the execlp() system call, but yet here I am. Let me get straight to the issue. The man page of execlp declares the system call as int execlp(const char *file, const char *arg, …); with the description: The const char arg and subsequent ellipses in the execl(), execlp(), and execle()
How does the fork() know whether it is in child process and in parent process? [closed]
Closed. This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 9 years ago. Improve this question When a fork() system call gets executed , the processor turns into kernel mode. Thus at the end of the