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Tag: linux

Recode value in the column in unix with awk or sed

In the following file, The values of 6th column for the rows who have values other than 1 or 2 in sixth column should be replaced with -9. How can I do it? old.fam new.fam should be Edit: I used cat old.fam | awk ‘{ if ($6==1 || $6==2) {print $1 ” ” $2 ” ” $3 ” ” $4

How to apply regex to specific column in awk

This will colorize the output of ls -lhAXF How to apply the color to specific type of item using regex, for example i want the folder to be green, the .config folder red, the regular file blue or something like that. folder – match $9 column containing ‘/’ in the end of word hidden folder – match $9 column containing

Can’t compile sample bpf program, bpf/bpf.h is missing

I’m trying to compile the sample bpf program in Linux source code. So I downloaded the current kernel source code and entered samples/bpf folder Then I tried to compile a sample program with gcc: And I’m unable to find bpf/bpf.h with apt-file What was wrong? Answer The Linux eBPF samples come with a rather long Makefile. It handles a lot

converting 4 digit year to 2 digit in shell script

I have file as: Here the 1st column represents dates as YYYYMMDDHH I would like to write the dates as YYMMDDHH. So the desire output is: My script: It is printing Any help please. Thank you. Answer Please don’t kill me for this simple answer, but what about this: You simply cut the first two digits by showing character 3

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