I have found a simple solution to my actual requirement, but I would still like to understand how to use the regex equivalent of the single character wildcard ? which we use for filtering … in say ls I would like to rename a group of files which differ by one character. FROM TO As I said above, my simple
Tag: rename
Batch copy and rename multiple files in the same directory
I have 20 files like: Files have a similar format in their names. They begin with 01, and they have 01*AAA*.sh format. I wish to copy and rename files in the same directory, changing the number 01 to 02, 03, 04, and 05: I wish to copy 20 of 01*.sh files to 02*.sh, 03*.sh, and 04*.sh. This will make the
linux_rename files in directory by prepending with timestamp using find command
I am trying to rename files in current directory by prepending timestamp value using find command like below But getting ‘Can’t move, no such file or directory error’, but appending works well with below command, not sure what is the difference between two. Answer Try this
linux command rename dates (YYYY.MMDD) to numbers(001,002,…,066,067) sequentially
I have renamed many files by using ‘rename’. However, I find a problem with conversion dates to numbers. The file name is 2021.0801, 2021.0802, .. etc. (Year.Month&date) I need to change Month&date parts to numbers of 001, 002, etc. So I need to rename to I saw I can do it when I use rename or #, ? but I
How to quickly rename my files on macOS or linux from CLI?
Here’re my source files. I need to figure it out a way to rename all the files to remove the first 36 characters up to _file or replacing as something else. I am expecting all the files are as below. Thanks in advance! Answer You can use rename like this: If you are on macOS, you can install rename with
Renaming Sequentially Named Files with Date Embedded
The Situation: I have hundreds of zip files with an arbitrary date/time mixed into its name (4-6-2021 12-34-09 AM.zip). I need to get all of these files in order such that (0.zip, 1.zip 2.zip etc) with in a Linux cli system. What I’ve tried: I’ve tried ls -tr | while read i; do n=$((n+1)); mv — “$i” “$(printf ‘%03d’ “$n”).zip”;
Can someone help me with rename tool? [closed]
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rename files which produced by split
I splitted the huge file and output is several files which start by x character. I want to rename them and make a list which sorted by name like below: part-1.gz part-2.gz part-3.gz … I tried below CMD: for (( i = 1; i <= 3; i++ )) ;do for f in `ls -l | awk ‘{print $9}’ | grep
Remove part of file name in multiple sub directories
The main folder “Main” contains multiple subfolders (6900,159, 9997, …) and each subfolder contains 8 items (4 files (6900Log.final.out, 6900Log.out, 6900Log.progress.out, 6900SJ.out.tab), 3 folders (6900_STARgenome, 6900_STARpass1, 6900_STARtmp), and one compressed file (6900Aligned.sortedByCoord.out.bam)). The 6900_STARtmp contain further subfolders but I don’t want to change name of sub folders present in 6900_STARtmp. Please see the image I want to remove 6900 from
Linux rename with a variable character?
I have a list of files eg. How do I use rename to be like this: I am new to this and having trouble understanding the examples online. I want to do something like the following where the ? is a variable character: Answer ? mean “any character”. So, your page-1.htm will be rename because it’s match with pattern page-?.htm