This works: But when I try to sort the the filenames, remove the newline the list of filenames that are piped to cat look identical to the previous but sorted: However cat returns this error: Answer Your xargs statement is expecting null terminated entries. If your filenames or directories have spaces, then yes, use the null terminated way.
Tag: sorting
Bash sort ignore first 5 lines
I’m having trouble ignoring the first 5 lines of my file while sorting the rest. My current command sorts the entire file by the second item, however I need to skip the first 5 “header” lines. I need read it and write it to the same file. Current Command Example Answer This sorts lines 6 and after of the file
sorting rows of a data file with Linux
I would like to sort the lines of a data file (each line idependent from each other) from the first character. For example, if I have a data file I would like to end with something like I have tried to do it using the sort command, but it sorts the columns (not the line). Transposing the data file +sort
Grouping and deleting Files
I have to come up with a solution to delete all files but the newest 2 in a directory stucture of our owncloud. The be exact – its the file versioning folder. There are files in one folder with the following structure: Filename.Ext.v[random_Number] The hard part is that there are different files in one folder I need to keep. IE:
Bash: Sort text file by bytewise case sensitive sort command or using python sort command
Text File using sort -s (case sensitive) using sort -f (Not case sensitive) The words starting with an uppercase are sorted alphabetically between the lowercase words. What I want is that the words in uppercase are at the start of each next letter (upercase alphabetically sorted): Expected output: How can I realize this using bash or python sort command? Answer
Linux – Sort files by part of name (no delimiters)
I want to get a sorted list of files. Files have the following naming convention: DATENUMBER.txt (without spaces). E.g., file 3 on 2015-12-09 looks like: 201512093.txt The version sort option of ls doesn’t help me: sort -V, –key=1.[number] do not work too as I have different filename length. As I have no delimeter between the date and the number, sort
Find command with size and time and sorted by timestamp
I have the following folder setup for example I need to recursively list them with file size, modification time and sorted by modification time recent first. I have tried the below without size… Any pointers? Answer %T+ – modification time (and date) %s – size %p – path of file
Sorting of data in descending order
Allow me to clarify my query: I have a database with thousand of character strings, followed by some values (based on scoring matrix) There are equal values also present. I am trying to sort the data in descending order using: But the data is still disarranged. Also tried by adding -k argument. Is it possible that i could get the
sorting takes 2 hours on vagrant – approx 100m lines
What can I do to optimize this sort? I am running: and then: getting the following output: here’s the datatset that I am using: a preview of the original dataset: here are the details on the vagrant machine: What can I do to optimize this sort? Answer Split your data into several files, sort each file in parallel, then merge
Using linux sort on multiple files
Is there a way I can run the following command with Linux for many files at once? Answer I assume you have many input files, and you want to create a sorted version of each of them. I would do this using something like Now, this has the small problem that if you run it again, if will not only