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Changing python version on platform LSF job script on Linux server
I want to execute my python code on LSF, and problem is that the return of in lsf is 2.6.6 (r266:84292, Jul 22 2015, 16:47:47) [GCC 4.4.7 20120313 (Red Hat 4.4.7-16)] But my code has been written for python2.7. How can I change or assign the correct version of python to LSF job script. Answer I found the answer to
zsh option to generate the recomended options
There is a nice option when setting up zsh on Ubuntu However, on a fresh Arch Linux install the option is missing. Is there a way to have it (or maybe, I am being picky here) ? Answer This happens when you haven’t got a .zshrc and there’s a /etc/zsh/recommended.zshrc. If you say yes, it’ll just copy that one to
OpenCV 3.1 Upgrade Leads to Linker Errors on Linux
I’ve recently upgraded from OpenCV 2.4.11 to OpenCV 3.1 by following this guide. This sudo make install seems to have worked successfully and when I run pkg-config –modversion opencv, I get the appropriate version (3.1.0). But for some reason, I am now running into linker errors, and even simple programs are unable to compile, for example: returns the errors: main.cpp:-1:
Rabbitmq remote call with Pika
I am new to rabbitmq and trying to figure out how I can make a client request a server with information about memory and CPU utilization with this tutorial (https://www.rabbitmq.com/tutorials/tutorial-six-python.html). So the client requests for CPU and memory ( I believe I will need two queues) and the server respond with the values. Is there anyway to simple create a
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Have a badly formatted tsv file with empty fields all over the place. I wish to fill these empty spaces with “NA” on linux. I tried awk ‘{gsub(“tt”,”tNAt”); print$0)’ but that only substitutes one empty space to NA instance. Chaining the command awk ‘{gsub(“tt”,”tNAt”); print$0)|awk ‘{gsub(“tt”,”tNAt”); print$0) does two substitutions per line – but not particularly helpful if I have
How to invert the l-flag of grep
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SigCgt value is not getting updated in /proc//status file?
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Why ls -Q give output as “Z\1” if the file name is ‘Z1’?
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